f(1) = 0 because if you plug in x=1 for the equation f(x)=(3x^2-4x+1)/(3x-1) it becomes f(1)=(3(1)^2-4(1)+1)/(3(1)-1) which becomes (3-4+1)/(3-1) which becomes 0/3 which is 0.

f(0) = -1 because if you substitute in x=0 into the equation, it becomes (3(0)^2-4(0)+1)/(0-1) which becomes 1/-1 which is -1

f(-1) = -2 because once again if you plug x=-1 into the original equation you get (3(-1)^2-4(-1)+1)/3(-1)-1 which becomes (3+4+1)/(-3-1) which becomes 8/-4 which is -2

Question

f(1) = 0 because if you plug in x=1 for the equation f(x)=(3x^2-4x+1)/(3x-1) it becomes f(1)=(3(1)^2-4(1)+1)/(3(1)-1) which becomes (3-4+1)/(3-1) which becomes 0/3 which is 0.

f(0) = -1 because if you substitute in x=0 into the equation, it becomes (3(0)^2-4(0)+1)/(0-1) which becomes 1/-1 which is -1

f(-1) = -2 because once again if you plug x=-1 into the original equation you get (3(-1)^2-4(-1)+1)/3(-1)-1 which becomes (3+4+1)/(-3-1) which becomes 8/-4 which is -2