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41 = 2/5x - 7 (X=?)
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Is this the expression?\[\frac{2}{5x} - 7 = 41\]
yes
Or is it ?\[\frac{2}{5x-7}=41\]
first one
Add 7 to both sides of the equation\[\frac{2}{5x}\cancel{-7}(\cancel{+7})=41(+7)\] and then multiply each side by 5x.
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5 times 2 or 5 times 41 and 7
\[(/\cancel{5x})\frac{2}{/\cancel{5x}}=(5x)48\]
ok
I made this more complicated than it needed to be..... to solve for x you want to get just x on one side of the equation so you can divide both sides by (5)(48)\[\frac{2}{(5)(48)}=x\frac{\cancel{(5)(48)}}{\cancel{(5)(48)}}\]
ok
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