Question

solve the question:
4(d-3)=2d

and

s+2-3s-16=0

Answer 1

do you know how to distribute numbers into parenthesis?

Answer 2

this is how i solved it before i got lost
4d-12=2d
-2 -2
2d - 12

Answer 3

almost right, you did it in your head correctly but not on paper
4d-12=2d
-2d -2d
2d-12=0

Answer 4

you weren't missing much so far,

Answer 5

does that make sense?

Answer 6

ohhhh ok ...
the second one
s+2-3s-16=0
+3 +3
4s+2-16=0
4s-14=0
+14 +14
4s = 14
/4 /4

Answer 7

s+2-3s-16=0
reverse distribute (factoring)
(1-3)*s +2-16=0

Answer 8

following?

Answer 9

mhmm so it has to equal 0?

Answer 10

no, let's do this step-by-step

Answer 11

okk

Answer 12

this time let's separate the s's from the numbers (move numbers to other side of equals sign
s+2-3s-16=0
-2 -2
on the left side the 2 and -2 cancel eachother out, so we get
s+2-2-3s-16=0-2
s-3s-16=-2

Answer 13

does this approach to this problem make more sense

Answer 14

s-3s-16=-2
+16 +16
s-3s-16+16=-2+16
s-3s=14

Answer 15

ohhh it does. ok .

Answer 16

sub. s by 3s?

Answer 17

last two steps are to combine the terms that contain s in them (s-3s) and then dividing by the coefficient in from of s

Answer 18

that is actually meaning one s minus 3 s

Answer 19

1s-3s=14

Answer 20

ok so -2s=12
/12 /12
s=-6?

Answer 21

sooooooo close

Answer 22

opssss

Answer 23

-2s=14
s=-7

Answer 24

great, you found the error, good job!

Answer 25

-2s=14
/14 /14

s= -7 ?

Answer 26

yup

Answer 27

woww that wasnt that hard...omg thanks you

Answer 28

we are actually dividing both sides by -2

Answer 29

good luck