|x+1|=2x
kinda obvious what x is but i dont kno how to explain or do this 1 mathmetically
if |y|=a then \[y=\pm a\] so |x+1|=2x gives (x+1)= 2x or (x+1)=-2x can u solve these two to get 2 values of x ?? out of these 2 ,one after re substituting in original equation,will not give u equality.so u discard that vale. then u will have only 1 solution.
@hartnn so how do i do |x+1|=2x
subtract 1 from both sides? @hartnn
as i have explained,u have (x+1)= 2x or (x+1)=-2x u need to solve both of these take one at a time x+1=2x subtract x from both sides,what u get??
1x? @hartnn
right?
1x where on left side or right side?
right side @hartnn
so whats on left side??
um is it 1
yup,so u have 1x=1 that is x=1 is one of your solution. can u get other solution similarly ?
Thanks and i'll try
so the second on is |x+1|=-2x right? @hartnn
(x+1)=-2x u can remove mod | | sign,since u are taking -2x
is x=-3 correct?
@hartnn
nopes, u get 3x=-1 so x=-(1/3) but when u put this in original equation,equality does not get satisfied, so the only solution u have is x=1 ok?
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