Can someone explain this? sqrt(x+3) + x +3 = sqrt(x+1)[1+sqrt(x+3)]
\[\sqrt{x+3} + x + 3 = \sqrt{x+1} (1+\sqrt{x+3})\]
This is an eqn - open the brackets and start raising in 2-nd degree
I'm just trying to figure out how they factored this
\[\sqrt{(.....) * (...)} =\sqrt{(.....)}\sqrt{(...)}\]
Only you made a small typo : it should be:\[\sqrt{x+3} + x + 3 = \sqrt{x+3}(1 + \sqrt{x+3})\]
ahhh, I did not make the typo, that is straight out of a textbook.
even so, how do you pull out an sqrt(x+3) from x?
See the rule of root multiplication that I posted for u above - the content "merges" and multiplies
start by dividing everything by \[\sqrt{x+3}\]
@Mikael, but we are not multiplying anything to begin with...?
\[x+3=\sqrt{(x+3)*(x+3)}=\sqrt{(x+3)}*\sqrt{(x+3)}\]
You do multiply - ON THE LEFT HAND SIDE !
Sorry RIGHT HAND SIDE
OPEN the parentheses - u have to multiply
@juantweaver how does x+3=sqrt((x+3)∗(x+3))
another example\[2=\sqrt{2*2}=\sqrt{2}*\sqrt{2}\]
Come ON\[\sqrt{A}*\sqrt{A} = \sqrt{A^2} = A\]
oohh k thanks
:}
close the question pl
koala vs. gator :P
No we live indifferent Eco-niches and therefore are smiling at each other :]]]
I am on top (of the forest) and gator is ... hmm, well you know...
Please close the question @baldymcgee6
Please close the question @baldymcgee6
sorry, battery died.
Thanks for "fan" meet u again but also u have to read beforehand u ask
Read what before I ask?
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