Question

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Answer 1

\[\frac{x-1}{(x-3)(3x-5}=\frac{a}{x-3}+\frac{b}{3x-5}\]
\(a\) is what you get when you replace \(x\) by 1 in
\[\frac{x-1}{3x-5}\] and \(b\) is what you get when you replace \(x\) by \(\frac{5}{3}\) in
\[\frac{x-1}{x-3}\]

Answer 2

sorry i meant replace \(x\) by 3, not by 1

Answer 3

ok