What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ?

I NEED DIRECTION NOW! Thanks

Question

What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ?

I NEED DIRECTION NOW! Thanks

anonymous · Answer

attachment

noelgreco · Answer

$$E = k \frac{ Q }{r ^{2} }$$

Calculate that for each point charge.  Then we'll add the vectors.

anonymous · Answer

How do you find direction?

anonymous · Answer

Addition of vectors

anonymous · Answer

http://www.youtube.com/results?search_query=Addition+of+vectors&oq=Addition+of+vectors&gs_l=youtube.3..0l7.1425.1425.0.1904.1.1.0.0.0.0.329.329.3-1.1.0...0.0...1ac.Dei6BcWaiZU

anonymous · Answer

http://www.youtube.com/watch?v=TAjJO1m4W_k

anonymous · Answer

the answer is in degrees? I need how to find the angle

noelgreco · Answer

The direction of an electric field is the direction of the force on a positive test charge placed in the field.  In this case the field is directed away from each of the positive charges.

anonymous · Answer

hag - you'd be surprise but there are topics which u actuall y need to read and understand in detail. And this is it

anonymous · Answer

http://www.youtube.com/watch?v=TAjJO1m4W_k

anonymous · Answer

|dw:1346438409410:dw|
$$A=k3*10^{-9}/\sqrt{125}^2$$
$$B=k3*10^{-9}/5^2$$

anonymous · Answer

The whole purpose of Openstudy is to surpass the inadequacies of current internet education by expounding concepts to people personally and helping their unique problems. Now that openstudy has been established, any less than that is a failure on the educators' parts.

anonymous · Answer

Vector addition is simple- put the end of one on the point of the other (in any order), and take the final result.|dw:1346438644261:dw| Think of a parallelogram

anonymous · Answer

The length of the arrows= the values in the equations above.