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sin (11pi/12) find exact value
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If you let pi = 180, you could put it degree form and figure it out from there.
or you can think of it this way: \(\large sin(\frac{11\pi}{12})=sin(\frac{\frac{11\pi}{6}}{2}) \) .... Half-angle formula anyone?
Now why would anyone want to do it that way?
After simplifying I get \(\sin(165^{\circ})\)
hmmm so it would be \[(\sqrt{6}+\sqrt{2})/4\]
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Which can be further broken down to \(\sin(120 + 45)\)
Okay, so which hint did you use...mine or dpalnc?
yours :O
Awesome
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