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Use the functions (x+1)/(x-3) and g(x)=(x+2)/(x+3) to find and simplify ex 1. (f+g)(x)
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Is f(x)=(x+1)/(x-3)
yes, sorry about that
Now, (f+g)(x)=f(x)+g(x)=(x+1)/(x-3) + (x+2)/(x+3) ={(x+1)(x+3) + (x+2)(x-3)}/{(x-3)(x+3)}
does that help?
why over x-3 x+3?
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Take LCM
is it (x+1)(x+2)?
(f+g)(x)=f(x)+g(x)=(x+1)/(x-3) + (x+2)/(x+3) ={(x+1)(x+3) + (x+2)(x-3)}/{(x-3)(x+3)} ={x^2+3x+x+3+x^2-3x+2x-6}/{x^2-3^2} ={2x^2+3x-3}/{x^2-9}
got it?
no :(
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nvm i got it
is that the answer?
Yes thats the answer
just simplified it
@YesterdayiSaidTomorow
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thanks :)
welcom
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