Question

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Answer 1

Hint: Use the quadratic formula to solve.

Answer 2

\[x={-b \pm \sqrt{ b^2-4ac} \over 2a}\]

Answer 3

Make sure it isn't factorable first before attempting to use the quadratic formula

Answer 4

It is factorable

Answer 5

Split the middle term to get
24x^2+40x + 21x + 35 = 0

Answer 6

Now factor by grouping

Answer 7

Well, now, everything looked good except for the fact that you forgot to set things equal to zero

Answer 8

You must remember to set it equal to zero then actually solve for x when you get to that part. Otherwise you end up with incorrect values for x due to attempting to take shortcuts.

Answer 9

8x(3x+5)7(3x+5) = 0
(3x+5)(8x+7) = 0

Now make sure to set things separately equal to zero, then actually solve for x

3x + 5 = 0
8x + 7 = 0

When you actually solve for x, you'll notice you get different values for x than the ones you currently have.

Answer 10

x = -5/3, -7/8

Answer 11

You're still being lazy with this. You shouldn't

Answer 12

Curiosity killed the cat, but laziness destroys intelligence

Answer 13

No, not a teacher yet, just a lowly student pursuing math degree

Answer 14

There's so many other things I can do besides become a teacher.

Answer 15

I can't deal with students in a classroom. I'll show you an example of what I can't deal with.

Answer 16

I would not want to be this teacher:

http://www.youtube.com/watch?v=0j-Vr_y0ono

Answer 17

No, I cannot

Answer 18

You're missing out on so many things by not having access to youtube. There are countless educational videos on youtube so that's a shame.

Answer 19

Khan Academy, one of the best educational sites posted his videos on youtube.

Answer 20

Oh I see. Well, watch it tomorrow, then.

Answer 21

although...quadratic formula is still usable even if the expression is factorable..