how do you solve: 7-3|4x-7|4
Anyone? please help

Question

how do you solve: 7-3|4x-7|>4
Anyone? please help

anonymous · Answer

subtract both sides by 7, got it ? can u do next step?

anonymous · Answer

then devide by -3 both sides ...

anonymous · Answer

thanks got it!

anonymous · Answer

ok , then we have absolute value , it will have 2 value , change the sign also when add negative

anonymous · Answer

wait I looked at the answer and I got the signs mixed up!  umm can u do it so I can see where I messed up?

anonymous · Answer

do I divide by -3 or multiply it?

anonymous · Answer

dived by -3

anonymous · Answer

7-3|4x-7|>4
-3|4x-7|>-3
|4x-7|> 1
4x-7 > 1 or 4x -7 < -1
your turn

anonymous · Answer

if you want you check the answer, replace the answer to the x , if both sides equal , that's correct

anonymous · Answer

ohh i see where I went wrong.. I forgot to change the sign whe  I divided by -3! haha

anonymous · Answer

ok, try again

hartnn · Answer

|4x-7|< 1
isn't it ? @linhtran

anonymous · Answer

I got the right answer.. i checked..

anonymous · Answer

when u take off the absolute valute, the sign will chage, if not , you cannot change sign yet

anonymous · Answer

can u help me with another one?

anonymous · Answer

ok, i'll try...

hartnn · Answer

when u multiply/divide by negative quantity
the sign flips !

anonymous · Answer

4+2|3x-5 all over 2|>5

anonymous · Answer

all over?

anonymous · Answer

$$\frac{ 3x-5 }{ 2}$$

hero · Answer

I see that someone is actually making an effort to actually explain things.

anonymous · Answer

?

anonymous · Answer

|dw:1346385909238:dw|

anonymous · Answer

yes

anonymous · Answer

subtract both side by 4 
then dived both sides by 2

anonymous · Answer

Im confused when I divide by 2 with the fractions... can u explain?