Help for Algebra 1.
where are you up to
just started.
do you understand the first question?
no like, I've done it. but I just need to check through.
yeaa
for the first question. I have to do it in PEMDAS but i dont know how to do it.
What do you have so far for A)
ughh.my friend says it's wrong. i got (-10) + (-2) + (-1) + 3b + b - 14 -3 +25
it was just a guess. cuz i didn't know how to do it.
thats a good start you have got the plus and minus operators
you will also need × and ÷ , also you will need to give one term an index say \(b^{-2}\)
and bracket a group of terms instead of justa single term
i understand the first question now. I got : (-10/ -2 + -1exponent3 ) + 14 +3b +b
^
well done :) still i dont see two operations in ur expression : multiplication(x) and subtraction(-)
(-10/ -2 + -1exponent3 ) + 14 x 3b - b
dont forget 25, also you might want to write \((-1)^3 \)as (-1)^3
(-10/ -2 + -1^t3 ) + 14 x 3b + b - 25
ignoring that 't' your answer is great ,
okai. so now simplify... can u give me tips on simplify?
just remember order of operations and you should be fine
note that -1^3 is different to (-1)^3
... how ?
okaii. I got my way tru the all the question. but i need help on the last question. i dnt understand.
you familiar with absolute values ?
sorta
great ! the last question asks to : 1) change each of the given values to absolute value. 2) and use in the expression 3) simplify 4) compare with old result
you're given the values : {14, 3, -2, -1, 3b, b, 25, -10,}; for ex, absolute value of -2 : |-2| = 2 you should use 2 in the expression, instead of -2
okai.. but how about division s and teh exponents ?
they all remain same. structure of expression remains same. just u need to change the input values !
give a try !
(10/2 + 1^3 ) + 14 +25
ryte??
you're almost correct :) is this your old expression : (-10/ -2 + -1^t3 ) + 14 x 3b + b - 25 ?
ohhh ughhh so then ... idk
@ganeshie8 you there?
Join our real-time social learning platform and learn together with your friends!