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Explain how to solve 8(to the 2nd power)+ 9(12 ÷ 3 • 2) – 7
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first do the (12/3 x2)
\[8^2+\frac{9(12)}{3* 2}-7\] or \[8^2+\frac{9(12 *3)}{ 2}-7\]?
That doesn't really make sense what does the problem inside of the parenthesis equal I can figure out the rest.
It's 8 right?
8
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What did you get overall?
577 but I think I did something wrong.
Yeah, I didn't get that. After you found what's inside you should have: \[8^{2}+9(8)-7\]
PEMDAS... you are on E
So wouldn't it be 64 + 9 x 8 - 7?
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Yes... now M
64 x 8?
9 into 8 first?
9 x 8?
yes
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9x8
72
yes 64+72-7
Now A and S
129?
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Awesome :D
Thanks you puppy man! haha
woof!
lol
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