Question

(2x+3)(2x^2-5x-3)

Answer 1

Hint:

(2x+3)(2x^2-5x-3)

expands out to

2x(2x^2-5x-3) + 3(2x^2-5x-3)

Answer 2

then it's (4x^4-10x^2-5x-3)+(6x^2-15x-9)

Answer 3

is that right?

Answer 4

2x(2x^2-5x-3)

should be

4x^3 - 10x^2 - 6x

Answer 5

i man 4x^3

Answer 6

ok and then what do i do next?

Answer 7

So

2x(2x^2-5x-3) + 3(2x^2-5x-3)

becomes

(4x^3 - 10x^2 - 6x) + (6x^2 - 15x - 9)

Answer 8

Now combine like terms

Answer 9

ok can you show me how to do that..that's the part i get confused on

Answer 10

-10x^2 and 6x^2 are like terms for instance, so you combine them to get

-10x^2 + 6x^2 = -4x^2

Notice how -10+6 = -4

Answer 11

Do the same with the other like terms

Answer 12

so the i would get 4x^3-4x^2-21x-9

Answer 13

you nailed it, nice work

Answer 14

ok so then i break them up into two ( )( ) right

Answer 15

no nvm thats wrong

Answer 16

what's wrong? the final answer you got was correct

Answer 17

im doing polynomials so i'm supposed to end with x=_ and x=_ at the end

Answer 18

the original problem is an expression and not an equation, so you can't solve for x

Answer 19

something is missing here

Answer 20

i forgot =0 at the end

Answer 21

oh then you just do this

Answer 22

(2x+3)(2x^2-5x-3) = 0

2x+3 = 0 or 2x^2-5x-3=0

Now solve each equation separately

Answer 23

the first one would be -2/3 right?

Answer 24

-3/2

Answer 25

ok and then it 2(x ) (x )

Answer 26

2x^2-5x-3=0

2x^2-6x+x-3=0

(2x^2-6x)+(x-3)=0

2x(x-3)+1(x-3)=0

(2x+1)(x-3)=0

Answer 27

-1/2 and 3

Answer 28

you got it

Answer 29

thank god! thanks so much!

Answer 30

so the three answers are: -3/2, 3, -1/2

Answer 31

you're welcome

Answer 32

yes! thanks!

Answer 33

yw