How many ways are there to correctly answer 2 out of 7 true or false questions
First thought is that each question has 2 possible answers, so might need to consider multiplication rule as well.
This is a binomial setting, I think.
Oh, fail :) not as easy as I thought it was. lol
7 trials, 2 possible outcomes each with fixed random probability.
the 7-choose-2 formula will be used as the binomial coefficient.
The setting asks for 2 successes and 5 failures, but both have the same random probability, so (.5)^2*(.5)^5 is simply (.5)^7 - the same as the probability of any ratio of correct:incorrect out of 7. This is where you multiply by 7C2 to find the number of ways.
This is, of course, assuming that the questions are answered purely randomly (via flip or coin or similar), and the test-taker is not actually trying to answer any correctly - that would change the probabilities of each individual trial and you'd have to use a multi-nomial formula (and likely also Bayes' Theorem to compute those probabilities in the first place). Simplifying assumptions are good things!
Do you need the formula for the binomial coefficient?
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