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6y^2-22y-40=0
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use quadratic formula to find the roots...
IT'S A QUADRATIC EQUATION.....FACTORIZE
by 2
2y(3y-11-20)
FIND TWO NUMBERS THAT GIVES A PRODUCT OF -240 AND A SUM OF -22
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IT'S -30 AND 8
THEN WRITE IT THIS WAY. . . 6y^2-30y+8y-40
okwhere did you get -240 and-22
-22 is the middle value.... i could have used just -40 but since y^2 has a coefficient which is 6 i multiply -40 by the coefficient before solving
-22 is d coefficient of the middle value
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ok
can u finish it now?
whats the next step
group it in two places then factorize.... 6y(y-5)+8(y-5)
the values inside the brackets are similar so we end up with...(6y+8)(y-5)
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and remember (6y+8)(y-5)=0
that implies that 6y+8=0. . . OR y-5=0
so the answers would be (-8/6,5)
yes
ok thanks
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