Question

how to simplify 8xy+12x^2y-6x^3/6xy

Answer 1

you should be able to do this the same way as the previous, by separating and finding common factors

Answer 2

wouldn't you mulitply 8xy^2 and 12x^2y by 2xy?

Answer 3

no as you have the following currently:

8xy+12x^2y-6x^3/6xy

and if you rearrange this like you did before you will get:

8xy/ 6xy + 12x^2y/6xy - 6x^3/6xy

now you can begin to divide each once individually

Answer 4

oh im sorry it's not 6x^3/6xy it's 6x^3/2xy

Answer 5

like only the last set of numbers are divided

Answer 6

so it's like 8xy^2/1 + 12x^2y/1 - 6x^3/2xy

Answer 7

ah ok, in which case you only need to divide the last term and then look for a common factor

Answer 8

or as you previously stated you could multiply them all by 2xy and then look for a common factor

Answer 9

soo 8x^2y+12x^2y-3x^2y ?

Answer 10

and then what?

Answer 11

not sure what you have done there, did you mutliply them all by 2xy or try dividing the last term?

Answer 12

8xy^2/1 + 12x^2y/1 - 6x^3/2xy

multiply them all by 2xy gives:

16x^2y^3 + 24x^3y^2 - 6x^3

now you look at these terms and look for a common factor

what do they all have?

Answer 13

2 ?

Answer 14

yup, they all have a 2. any of the letters in all of them?

Answer 15

2x

Answer 16

they all have an x, but they actually all have an x^2 term so you would have a common factor here of 2x^2

Answer 17

ohhh okayy

Answer 18

then it would be 8y^3=12xy^2-3x ?

Answer 19

* -

Answer 20

in my book it says the answer should by 8xy^3+12x^2y^2-3x^2 / y

Answer 21

yup your answer is correct and so is the one in the back of the book

the answer in the back of the book just divided the last term and then left it there.

8xy^2/1 + 12x^2y/1 - 6x^3/2xy

divide 6x^3 by 2xy gives 3x^2/y

so you would have

8xy^2/1 + 12x^2y/1 -3x^2/y

then to get rid of the y on the bottom, you would multiply them all by y and get

8xy^3+12x^2y^2-3x^2

Answer 22

oh okay, thanks

Answer 23

no problem, hope you understood all that ok

Answer 24

Yes I did :)