Question

Radical expressions question ..

Answer 1

this is a rational question...

Answer 2

Tha's what I meant, my bad.

Answer 3

\[\huge \frac{x^2 + 6x + 8}{4 - x^2} \implies \frac{(x+4)(x+2)}{(4+x)(4-x)}\]
does that help?

Answer 4

So it's C, then...

Answer 5

why do you say so?

Answer 6

Becuase the top is positive, and the bottom is negative.

Answer 7

right ?

Answer 8

find something to cancel out

Answer 9

So then if I cancel the four it would be d for sure !

Answer 10

what did you cancel?

Answer 11

I'm confused !!

Answer 12

let me rephrase this... \[\huge \frac{(x+4)(x+2)}{(x+4)(4-x)}\]
4 + x can also be written as x + 4 because of commutatie property of addition


do you know what to do now?

Answer 13

4-x^2 = (2+x)(2-x)