Question

Find all intercepts and asymptotes y= x^2-4/(x^2-x-12)

Answer 1

For the vertical asymptotes, you need to find the values of x for which the denominator is zero\[x^2-x-12=0\]Solve this quadratic equation to get two values of x. Are you familiar with the kind?

Answer 2

so X cannot be -4 and positive 3?

Answer 3

correct.

Answer 4

Wait isn't it opposite now that I think about it.

Answer 5

(x+3)(x-4) = (x^2-x-12)?

Answer 6

Right, (x+3)(x-4) is in the denominator and if x = -3 or x = 4, then y = infinity. So x = -3 and x = 4 are the asymptotes.