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Mathematics 15 Online
OpenStudy (anonymous):

May someone PLEASE explain if I did this math problem correctly? http://img31.imageshack.us/img31/3674/idcboutlife.jpg I got 47, correct?

OpenStudy (lgbasallote):

can't you post screenshots? how come it's always blocked login?

OpenStudy (anonymous):

can you note see it?

OpenStudy (lgbasallote):

nope

OpenStudy (anonymous):

http://s11.postimage.org/80xv7plrl/idcboutlife.jpg

OpenStudy (anonymous):

how about that?

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

I think it's 37, is it i correct? :D

OpenStudy (anonymous):

Hello? :)

OpenStudy (anonymous):

67-20=47

OpenStudy (anonymous):

to find the range you just take the largest value and subtract the smallest value from it.

OpenStudy (anonymous):

Thank you! care to do another one? :)

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

http://i50.tinypic.com/35iwr2h.jpg

OpenStudy (anonymous):

is it 39?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

thanks! :) I have some more for ya. ;)

OpenStudy (anonymous):

it looks like you are doing them fine.

OpenStudy (anonymous):

http://i45.tinypic.com/16acweb.jpg

OpenStudy (anonymous):

TRUST ME, I do need help. is the answer 45?

OpenStudy (anonymous):

yes you got it.

OpenStudy (anonymous):

oh, another question! different format, but still, another question. :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Find the lower quartile and upper quartile. 2, 2, 7, 21, 27, 31, 46, 47, 52, 53, 55, 55, 56

OpenStudy (anonymous):

It it 46,56?

OpenStudy (anonymous):

look up what lower quartile and upper quartile mean, do you know?

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

The upper 25% (or 1/4) and the lower 25% Can you please tell me if it's right or not? :(

OpenStudy (anonymous):

its actually the mean of the bottom 50 % and the mean of the top 50 % To find the breaking point for the top and bottom, you start by finding the mean of the entire set.

OpenStudy (anonymous):

Ah, so... 2,56?

OpenStudy (anonymous):

sorry sorry whenever i said mean i should have said median

OpenStudy (anonymous):

So... are both of my answers wrong?

OpenStudy (anonymous):

First let's find the median (which means number that is listed and is in the middle) of the entire set. yes the answers are wrong so far.

OpenStudy (anonymous):

31, 46, Median is between that

OpenStudy (anonymous):

since we have an odd number of data numbers we will end up with an exact answer for the median

OpenStudy (anonymous):

how many numbers do we have?

OpenStudy (anonymous):

13

OpenStudy (anonymous):

so what number is exactly in the middle, you were close with your previous answer, but we only want one median

OpenStudy (anonymous):

46

OpenStudy (anonymous):

great! now we have the upper range (which is 46 thru 56) and the lower range ( which is 2-46) You must find the median of the upper and lower range.

OpenStudy (anonymous):

Side question: Find the interquartile range. 8, 8, 16, 20, 36, 37, 37, 51, 51, 54, 64, 70, 70 is it 41?

OpenStudy (anonymous):

upper: 53 lower: 21

OpenStudy (anonymous):

The interquartile range is = upper quartile - lower quartile

OpenStudy (anonymous):

your upper and lower are correct!

OpenStudy (anonymous):

Median is 37 for the bq~!

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

have you calculated the interquartile range yet?

OpenStudy (anonymous):

34

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

Wait... we have a problem... Find the interquartile range. 8, 8, 16, 20, 36, 37, 37, 51, 51, 54, 64, 70, 70 a.22 c.62 b.19 d.41 no 34!

OpenStudy (anonymous):

explain? please?

OpenStudy (anonymous):

i literally have to leave in less than two minutes. please, exlain! :(

OpenStudy (anonymous):

that is a little confusing. let me double check something

OpenStudy (anonymous):

Yeah...

OpenStudy (anonymous):

please, hurry!

OpenStudy (anonymous):

I have less than 27 seconds...

OpenStudy (anonymous):

9

OpenStudy (anonymous):

9

OpenStudy (anonymous):

lower is 18

OpenStudy (anonymous):

upper is 59

OpenStudy (anonymous):

59-18 =

OpenStudy (anonymous):

d

OpenStudy (anonymous):

i see what i did wrong now, you want an explanation still

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