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Mathematics 11 Online
OpenStudy (ghazi):

somebody please explain unit step function ...how come it is defined at zero...though there is a jump ...but still were are able to differentiate and integrate it from zero ....

OpenStudy (experimentx):

there are not really called functions ... rather generalized function and derivatives are called generalized derivatives.

OpenStudy (ghazi):

it would be great if you could make that generalisation more lucid...actually i am stuck and thinking of finding it other way..

OpenStudy (experimentx):

|dw:1346491565254:dw| this is your step function f(t) = u(t-t_0)

OpenStudy (experimentx):

the derivative at t=t_0, would be delta(t-t_0)

OpenStudy (ghazi):

|dw:1346491624874:dw|

OpenStudy (experimentx):

yeah ... that works as a switch.

OpenStudy (ghazi):

how you define derivative at 0?

OpenStudy (ghazi):

exactly that works as a switch with constant supply

OpenStudy (experimentx):

at 0, the derivative will be equal to ... value of jump times delta(t)

OpenStudy (ghazi):

well don't we count for jump..i mean definition of derivative

OpenStudy (experimentx):

at this particular case ... you jump is just 1

OpenStudy (experimentx):

http://en.wikipedia.org/wiki/Dirac_delta_function

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