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Mathematics 15 Online
OpenStudy (anonymous):

proportion-geometric mean. could somebody explain this plz.... see attached

OpenStudy (anonymous):

OpenStudy (anonymous):

that's got everything you need to know

OpenStudy (anonymous):

....i think

OpenStudy (anonymous):

seeing...

OpenStudy (anonymous):

thank you . i dont get why they are called means. do they form geometric sequence ? a/b = c/d b and c are means a , b , c , d form a sequence ?

OpenStudy (anonymous):

The situation depicted in your question can be summarized as: The condition is similar to inserting to Geometric means b and c, between a and d. On doing that, the numbers a, b, c, d will be in Geometric Progression, in which the ratio of the latter to the former term will always be equal to the common ratio of the sequence... So, according to above explanation, b/a = c/b = d/c Use the equality relation between the first and the last terms, you will get... b/a = d/c or, a/b = c/d

OpenStudy (anonymous):

thank you i get it xD

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