$$\huge \int (u^2 \div 3 \times u + 4u - 2u^3 \times u) du$$

Question

anonymous · Answer

good luck with that :)

anonymous · Answer

Can you separate them ??

lgbasallote · Answer

haha i know right >:))

lgbasallote · Answer

this is tricky depending on if you follow PEMDAS or VBODMAS

lgbasallote · Answer

@waterineyes *where* would you separate them?

anonymous · Answer

From plus and minus sign..

You will get three separate integrals..

lgbasallote · Answer

how would that look like?

anonymous · Answer

May be :

$$\int\limits (u^2 \div 3 \times u)du + 4 \int\limits u.du - \int\limits (2u^3 \times u)du$$

lgbasallote · Answer

so basically...the main problem is that $u^2 \div 3 \times u$ huh

anonymous · Answer

I think that will result into :

$$\frac{u^2}{3} \times u \implies \frac{u^3}{3}$$

lgbasallote · Answer

hmm you sure it's not $$\frac{u^2}{3u}$$??

anonymous · Answer

No..

According to PEMDAS, when division and multiplication occur simultaneously then we do the calculations from left to right..

So division is coming first..

Also according to BODMAS, Division comes before Multiplication..

lgbasallote · Answer

ahh very well. you pass :D

exept that last sentence...shouldn't have said that...

lgbasallote · Answer

except*

anonymous · Answer

Yeah I know that..
Sorry for that..

lgbasallote · Answer

lol