Question

i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps

Answer 1

There is an algebraic identity for such question.
You want to cube of (3x-1/3y).
Such type is identified by (a-b)^3.
i.e \[a ^{3}-b ^{3}-3ab(a-b)\]
Now put the value of a=3x and b=1/3y and solve it.

Answer 2

ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS

Answer 3

where do you get stuck

Answer 4

FROM THE FIRST STEP

Answer 5

see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...

Answer 6

WHAT DOES ^ THIS SIGN MEANS

Answer 7

raise to power of

Answer 8

ok yah am getting it then

Answer 9

now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\]
Which is equal to \[9x ^{2}/y\]

Answer 10

are you there