Order the group of quadratic functions from widest to narrowest graph. y=-4x^2, y=-3x^2, y=-5x^2
A.Y=-3X^2,Y=-5X^2, Y=-4X^2
B. y=5x^2, y=-4x^2 ,y=-3x^2
C.y=-3x^2,y=-4x^2,y=-5x^2
D.Y=4X^2, y=-3x^2 , y=-5x^2
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OpenStudy (anonymous):
(A)
OpenStudy (anonymous):
Check B). You seem to have a typo.
OpenStudy (anonymous):
o
OpenStudy (anonymous):
is that a conformation?
OpenStudy (anonymous):
ok now look lol
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OpenStudy (anonymous):
i think B) is y=-5x^2, y=-4x^2, y=-3x^2
OpenStudy (anonymous):
If y=ax^2 the magnitude of a depends the width of the graph........ lower the magnitude of a wider the graph
OpenStudy (anonymous):
so, what do u think?
OpenStudy (anonymous):
@rajathsbhat i dont think that is correct
OpenStudy (anonymous):
it is now lol
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OpenStudy (anonymous):
Hey, the length of the latus rectum is 4a, right?
So, greater the "a", longer is the latus rectum, wider is the graph!
OpenStudy (anonymous):
now i think it is (B)
OpenStudy (anonymous):
& you are right!
OpenStudy (anonymous):
Look at the sign dude they are negative
OpenStudy (anonymous):
Dude, that only means the parabola in facing down, that's all.
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OpenStudy (anonymous):
So, we need to take the magnitude only
OpenStudy (anonymous):
Can u PLZ draw a graph
OpenStudy (anonymous):
for each and see
OpenStudy (anonymous):
I'll try.
OpenStudy (anonymous):
ooo. You r right!, @saurav. @ james, you should write it in the form \[x^{2}=-4ay & then compare "a".
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OpenStudy (anonymous):
I thought it was in the form \[y^{2}=-4ax\]
OpenStudy (anonymous):
U forget shakya
OpenStudy (anonymous):
lol. But the answer then is C isn't it?
OpenStudy (anonymous):
YEP...... its C
OpenStudy (anonymous):
The real asker is @85295james. So, do you get it, James?
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