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A student scores 72 out of 100 on a test. If the maximum score on the next test is also 100 points, what score does the student need to maintain at least an average of 80?
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let the score be x then (72+x)/2>=80
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The 2 tests' points add together to make 200. A percentage is in the form \[\ \frac{x}{100} \], So divide our 200 score by 2 to get it in 100-terms Call y the score on the 2nd test. We want \[\frac{72+y}{2}\] to equal at least 80 \[\frac{72+y}{2} >/= 79\]
can you help me through it
Re-arrange and find y
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@henpen why 79
not 80
Sorry, 80, the 'or equal to' sign was breaking on me!
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