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Mathematics 6 Online
OpenStudy (amtran_bus):

What is the coordinates of the hole in this graph? And how do you get the y coord part of it? f(x)=(x^2-4)/(x^2-x-2)

jimthompson5910 (jim_thompson5910):

Hint: Factor the numerator and denominator as much as possible

jimthompson5910 (jim_thompson5910):

Then see if anything cancels

OpenStudy (amtran_bus):

Thanks. It does, the (x-2) on the top and bottom. Then I know that the hole is at x-2=0, so it is at 2. But that is only the x coord. How do I get the y part so I can graph it?

jimthompson5910 (jim_thompson5910):

You now plug x = 2 into the simplified version of (x^2-4)/(x^2-x-2) to find the function value or the y coordinate

OpenStudy (amtran_bus):

God bless you!

jimthompson5910 (jim_thompson5910):

yw

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