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Having some trouble with exponential problems... Ok, so say you've got e ^(2x)=e ^(x+1). How would you go about finding a value for x? Alternatively, if you had 4^(-x)=2^(x+1) how would you find THAT x? Any help with either or both of those problems would be extremely useful :)
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On taking log on the both sides of the Eqn \[e ^{2x}=e ^{x+1} \] become 2x=x+1 Hence x=1 is the answer
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