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If h(x) = 3x − 1 and j(x) = −2x, find h[j(2)]. 11 −11 13 −13
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First thing you want to do is find the value of the function j(x) at x=2 Tell me what you get
2?
the function is j(x)=-2x, so plug in 2 for x
-4
perfect. Now you have h(j(2)), where j(2)=-4, so h(-4).
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use the same process you used above, but with the function h(x)=3x-1 at x=-4
did you get an answer?
-11?
close, make sure you keep track of your - signs
so just 11
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h(-4)=3(-4)-1
=-12-1
-13 oops
there ya go, you got it!
thank you!!
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you're welcome
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