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Mathematics 28 Online
OpenStudy (anonymous):

If h(x) = 3x − 1 and j(x) = −2x, find h[j(2)]. 11 −11 13 −13

OpenStudy (anonymous):

First thing you want to do is find the value of the function j(x) at x=2 Tell me what you get

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

the function is j(x)=-2x, so plug in 2 for x

OpenStudy (anonymous):

-4

OpenStudy (anonymous):

perfect. Now you have h(j(2)), where j(2)=-4, so h(-4).

OpenStudy (anonymous):

use the same process you used above, but with the function h(x)=3x-1 at x=-4

OpenStudy (anonymous):

did you get an answer?

OpenStudy (anonymous):

-11?

OpenStudy (anonymous):

close, make sure you keep track of your - signs

OpenStudy (anonymous):

so just 11

OpenStudy (anonymous):

h(-4)=3(-4)-1

OpenStudy (anonymous):

=-12-1

OpenStudy (anonymous):

-13 oops

OpenStudy (anonymous):

there ya go, you got it!

OpenStudy (anonymous):

thank you!!

OpenStudy (anonymous):

you're welcome

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