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Mathematics 8 Online
OpenStudy (anonymous):

Greatly Appreciate Any help!In △JKL, what is the length of KL? A. 33radical3 B.66 C.33radical2 D.16.5

OpenStudy (anonymous):

OpenStudy (anonymous):

this triangle just needs to be solved id use law of sines

OpenStudy (anonymous):

Sine is opp/hypo right?

OpenStudy (australopithecus):

just use SOH CAH TOA

OpenStudy (australopithecus):

see over view https://en.wikipedia.org/wiki/Trigonometry

OpenStudy (anonymous):

Im already aware that i need to use soh cah toa but i dont understand how to solve using the equations

OpenStudy (anonymous):

its just ratios so we have 33/sin30 = b/sin60

OpenStudy (anonymous):

b is just the value i gave to the side we want to solve for, so solve for b with this equation and you have your answer, kinda hard to explain how to solve for law of sines

OpenStudy (anonymous):

would cross multiplying be involved?

hartnn (hartnn):

side opposite to 30 is half the hypotenuse,so LJ=2*33 side opposite to 60 is \(\sqrt{3}\)/2 times the hypotenuse. so KL=\(\sqrt{3}\)/2*LJ can u find KL from this?

OpenStudy (anonymous):

ya we want b by itself so multiply both sides by sin60

OpenStudy (anonymous):

Well i multiplied sin60 with 33 witch gave me about 28.57 am i correct so far?

OpenStudy (anonymous):

no you cant use a calculator on this one, get the values of the sines with the unit circle. http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg

OpenStudy (anonymous):

but technically you are correct just your answer wont work with your options here

OpenStudy (anonymous):

oh okay so i would have to calculate with radical 3/2?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

So my result would be 33radical3?

OpenStudy (anonymous):

ya thats what i got

OpenStudy (anonymous):

Thank you very much for your patience Nick! (:

OpenStudy (anonymous):

np

OpenStudy (anonymous):

is there any way i can reward you here, im new here so im unaware of the benefits or regulations

OpenStudy (anonymous):

@RuthyCakes yes you can give him Medal by clicking on the "Best Response"

OpenStudy (anonymous):

thank you (:

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