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is this correct? solve for x 2(y-3)=-8(x-2) (-y=22)/4=x
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2(y-3)=-8(x-2) 2y-6=-8x+16 2y=-8x+22 divide by two on both sides y=-4x+11
ii need to solve for x
\[2(y-3)=-8(x-2) \rightarrow -\frac{1}{4}(y-3)=x+2 \rightarrow x=-\frac{1}{4}(y-3)-2\]
x=-(y-11)/4
Sorry, typo. should be +2 at the end there.
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\[2(y−3)=−8(x−2)→−\frac{1}{4}(y−3)=x-2→x=−\frac{1}{4}(y−3)+2.\] Then you can simplify from there.
|dw:1346606485452:dw|from here you could solve for x
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