Relations & Functions---------------------------for x3,f(x)=3x-2 and for -2≤x≤2,f(x)x^2-2
find f(0)+f(4)

Question

Relations & Functions---------------------------for x>3,f(x)=3x-2 and for -2≤x≤2,f(x)x^2-2
find  f(0)+f(4)

anonymous · Answer

$$f(x)  = \left\{\begin{array}{rcc}
x^2-2& \text{if}  & -2\leq x\leq 2 \
3x-2& \text{if}  & x >3
\end{array}
\right.
$$
?

wwe123 · Answer

yes and....

anonymous · Answer

then it is ok if you understand what it means
how do you find $f(0)$? first you ask what catagory  does 0 belong to, is  $-2\leq 0\leq 2$ or is  $0>3$ ? 
evidently it is the first one, which means  you use the first formula, i.e. 
$$f(0)=0^2-2=-2$$

anonymous · Answer

repeat with 4,
since $4>3$ you would use the second formula to compute $f(4)$
then add

wwe123 · Answer

please demonstrate more

anonymous · Answer

f(0)= 0^2 - 2 = -2
f(4)= 3(4) - 2 = 10
then f(0) + f(4) = -2+ 10 = 8