Question

What are the (x,y) coordinates of the vertex of the parabola y=x^2-4x+1?

Help please....

Answer 1

y=x^2-4x+1
convert this to vertex form:

y = (x - 2)^2 -4 + 1
y = (x - 2)^2 - 3

vertex is where the squared term is zero
that is when x = 2

can you calculate the y coordinate?

Answer 2

yesss

Answer 3

its 1

Answer 4

??

Answer 5

there u go then
the graph looks a bit like this

Answer 6

oops - no
plug x=2 into the equation
y = (2-2)^2 - 3
= -3