In the figure shown below, the small isosceles right triangles are congruent. The area of the square is 324 square iches. What is the total area, in square inchesm of the 2 small triangles? 90 160 180 324 648
Hint: imagine flipping the right-side triangle over the right side of the square.
hmmmm.
it'd be 90?
How much of the square would that triangle cover?
1/2
Right! So what would be the area of that triangle?
90
Umm, if the area of the square is 324, and the triangle is half that area, it would be.. ?
I would figure what is the length of 1 side of the square. that would be the base and height (both legs of isosceles are =) area of each triangle is (1/2) base* height for 2 congruent triangles, that adds up to base*height= s*s where s is the side of the square but s*s is the area of the square!
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