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Mathematics 7 Online
OpenStudy (anonymous):

shade soultion set to the system of inequalities x+3y>-4 2x+y<5

OpenStudy (anonymous):

First put them both in slope-intercept form (y=mx+b) so you can graph them easier.

OpenStudy (anonymous):

so 3y=x+(-4)

OpenStudy (anonymous):

Ok, now divide everything by 3 to isolate the y. And do a similar treatment to the other equation. And when you graph them, remember that they will be dashed lines not solid lines because the inequalities do not include 'or equal to.'

OpenStudy (anonymous):

(mm, should be a -x when you move it to the right side too.)

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

so is y -1/6

OpenStudy (anonymous):

Where did that number come from? It's a system of inequalities so there won't be any single number answer.

OpenStudy (anonymous):

i dont know i divieded by 3

OpenStudy (anonymous):

Hmmm. Here are the steps for the first inequality: x + 3y > -4 3y > -x - 4 y > -x/3 - 4/3

OpenStudy (anonymous):

Do the same kind of thing for the second inequality and graph both dotted lines using their slopes and intercepts. The shaded region is above the first line and below the second line.

OpenStudy (anonymous):

thanks

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