Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

y = x − 1 x= 3over2

y = x + 3 x= 3over2

y = −x − 1 -x=-2over3

y = −x + 3 -x= -2over3

Question

Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

 y = x − 1 x= 3over2

 y = x + 3 x= 3over2

 y = −x − 1 -x=-2over3

 y = −x + 3 -x= -2over3

anonymous · Answer

help please

anonymous · Answer

okay. the slope of the line is the opposite reciprocal of the line given
so it would become -1

anonymous · Answer

then all you would have to do is take the point -6,3 and plug it into the equation y=-1x+b

anonymous · Answer

does it make sense so far?

anonymous · Answer

Perpendecular <means algebraically> Slope2 * Slope1  = -1

anonymous · Answer

so you would do -6=-3+b
b=-3
the equation would be y=-x-3

anonymous · Answer

thank you!