Question

Given the linear equation y=1/3x - 3, find the y coordinates of the point (-6), (-3), and (6).

Answer 1

substitute x with the points

Answer 2

ok it would be -6/3 = 2 ?

Answer 3

y=1/3(-6)-3
y=-2-3
y=-5
so the first point would be at (-6,-5)

Answer 4

do the same for the other points
y=1/3(-3)-3
and
y=1/3(6)-3

Answer 5

so my second points would be (-3,0)

Answer 6

well if you do y=1/3(-3)-3
it becomes y=(-3)/3-3
y=-1-3=-4
so the second point would be (-3,-4)

Answer 7

ok i see

Answer 8

so this one would be y = 1/3 (6) -3
y = 2 -3
y = -1
(-1, -3)

Answer 9

nono you're solving for the y-coordinate given the x-coordinate, so the answer would be
(6,-1)

Answer 10

so the 6 they give you is the x coordinate and you just solved for the y coordinate which is -1 and then you just put them together

Answer 11

oh ok i got it now. thank you so much

Answer 12

np