139 gallons being drained at a constant rate of 12 gallons per day. write equation that models the number of gallons g after t days
day 1, 12 gallons drain out day 2, 24 gallons drain out day 3, 36 gallons drain out 12,24,36 are all multiplies of 12 defining variable let "t" be the number of days that have past 12t represents the amount of liquid that has drained out on the "t"th day you originally start with 139 gallons any ideas?
139g=12(t)
so t is 12
you are not solving for t you are trying to write an equation that represents how many gallons of liquid is left after "t" days f(t)= .....
so its g=12(t)
that only tells you how many gallons have drained out, not how many gallons are left remaining
day 0- 139 gallon day 1- 127 gallon day 2- 115 gallon day 3- 103 ...
day 0- 139 gallon day 1- 139 -12 gallon day 2- 139 -24 gallon day 3- 139 -36 gallon ...
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