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Find k such that the equation kx^2 + x +25k has a repeated solution.
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equation? u mean that thing equals 0?
So you need to make it a perfect square, I guess.
Good point, josiahh, no equals sign -> no equation.
It's what it says on my hw. ;c
Can reword it as 'polynomial has repeated roots' but we don't need to get bogged down in the wording...
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And it's saying something about using b^2 -4ac
I'll take it as a polynomial that has repeated roots as CliffSedge suggested. in this case just find the determinant and set it =0 1-100k=0. solve for k
sorry, 1-100k^2=0
+/- 1/10
yes
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That was it, thank you o: I thought it was gonna be more drawn out than that
ur welcome
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