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using the cancellation technique in calculus(limits) does: (2x^2 - x -3) / x + 1 simplify to: 2x^2 - 2 ?
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Divide everything by the highest power variable in the demominator and proceed with the limit. i.e Divide everything by x in the entire equation
btw, what is x approaching?
when dividing by x, you would need multiply by the reciprocal (1/x) which results in (2x^2 - x -3) / x^2 + x. that all cancels to 2-3. x is approaching -1
he meant multiply both top/bottom by 1/x easier way is to factor the numerator to --> (2x-3)(x+1) what cancels? then evaluate at -1
the (x+1) 's cancel and you are left with 2(-1) -3 = -5 correct?
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sorry...yes thats correct
thanks for the help man!! i really appreciate it
no problem
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