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Mathematics 7 Online
OpenStudy (anonymous):

If possible evaluate the function at the given values of the variable (f)x=sqaure root sign 5-5x x=-2,5 f(-2)=

OpenStudy (anonymous):

when you plug in -2, 5-5x=-5 . can you take square root of a negative number?

OpenStudy (anonymous):

I think no

OpenStudy (anonymous):

so your function is not defined at -2. you cannot complete the operation

OpenStudy (ash2326):

so f(-2) doesn't exist for a real function

OpenStudy (anonymous):

that option is there but says its incorrect

OpenStudy (anonymous):

square root 15 was the correct answer five was not a real number

OpenStudy (anonymous):

oh snap. sorry mate. -5(-2)=10... I totally misread the sign

OpenStudy (anonymous):

no worries maybe next time

OpenStudy (anonymous):

it is sqrt(15)

OpenStudy (anonymous):

I got half of it right

OpenStudy (anonymous):

alright. next time I will pay closer attention

OpenStudy (anonymous):

thanks for your help

OpenStudy (anonymous):

ur welcome

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