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If possible evaluate the function at the given values of the variable (f)x=sqaure root sign 5-5x x=-2,5 f(-2)=
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when you plug in -2, 5-5x=-5 . can you take square root of a negative number?
I think no
so your function is not defined at -2. you cannot complete the operation
so f(-2) doesn't exist for a real function
that option is there but says its incorrect
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square root 15 was the correct answer five was not a real number
oh snap. sorry mate. -5(-2)=10... I totally misread the sign
no worries maybe next time
it is sqrt(15)
I got half of it right
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alright. next time I will pay closer attention
thanks for your help
ur welcome
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