Question

this one is about factoring also...but a little bit nicer and harder\[p^x=y^4+4\]\(p\) is a prime...\(x,y\) are natural.

Answer 1

What are we supposed to do?

Answer 2

well...find all solutions

Answer 3

this one is not mine

Answer 4

it will be always odd
because lhs is an odd no

Answer 5

Oh.... got it can be both

Answer 6

how...lhs is (prime no)^natural no....so odd ...right?

Answer 7

p=2

Answer 8

oh...yes...for p=2 it'll fail

Answer 9

1...factor y^4+4
2...p^x=ab then a,b are some exponents of p

Answer 10

y^4+4=(y^2-2y+2)(y^2+2y+2)