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c(x)= -5/x^2-4
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nice to know
All right... what's the question?
\[c(x) = {-5 \over -4 + x^2} \]
\[c(x) = {0 - 5 \over -4 + x^2} \]
\[c(x) = {-5 \over (x + 2)(x - 2)} \]
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If \(f(x)\) stands for 'function,' then \(c(x)\) stands for cunction. Yes.
a^2 - b^2 = (a+b) (a-b) is ur question c(x)= -5/(x^2-4)??? or (-5/x^2) - 4????
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