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can you check my answer please..i'm not sure its correct :S..posted in replies
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\[\frac{ 3 }{ x+1 }=\frac{ 2 }{ x-1 }\] 2(x-1)=3(x+1) 2x-2=3x+3 2x-3x=2+3 -x=5 x=-5
you multiplied wrong...
should be 3(x-1) = 2(x+1)
what you did was 3(x+1) = 2(x-1)
so the answer would be -5 instead?
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3(x-1) = 2(x+1) 3x - 3 = 2x + 2 3x - 2x = 3 + 2 no i dont think it's -5
so its still positive 5?
yes it's +5 why "still"?
dont worry i'm getting muddled..
ah i see
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thankyou for your help..
welcome
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