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Using complete sentences, explain how you would factor completely x^9 – 64.
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8^2=64
4^3=64
Think of it like difference of cubes.\[(x^3)^3 - 4^3 \]
\[a^3 - b^3 \implies (a - b)(a^2 + ab + b^2) \]
... and then simplify.
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the a,b,c, is confusing me can you show me using the numbers in the problem?
a=x and b=4
im still really confused how would i factor x^9-64 like how would i split up the terms
@ghazi \(a = x^3\)
@ParthKohli :(
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@lukelebeau You could also go with this.\[ \large {a^9 - b^9} \implies (a - b) (a^2 + a b + b^2) (a^6 + a^3 b^3 + b^6)\]
@lukelebeau see \[(x^3)^3-4^3=(x^3-4)((x^3)^2+4*x^3+4^2)\]
so we facor x^9 first which is (x^3)^3?
yes
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