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Mathematics 14 Online
OpenStudy (anonymous):

3x^2-8x-11=13-6x

OpenStudy (anonymous):

Substract 13-6x from both sides.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

3x^2-8x-11=7x

OpenStudy (anonymous):

I mean: 3x^2-8x-11-(13-6x)=13-6x-(13-6x)

OpenStudy (anonymous):

ok then what would the next step be

OpenStudy (anonymous):

You have to put the equation in the canonical form: ax^2+bx+c=0 so you can use Bhaskara's Formula. Here we go, one step more to Bhaskaras: 3x^2-8x-11-(13-6x)=0

OpenStudy (anonymous):

ok then do i factor or combine like terms

OpenStudy (anonymous):

Combine: 3x^2-11-13+6x-8x=0 3x^2-2x-24=0

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

how did you get 24?

OpenStudy (anonymous):

wouldn't it be 6x-8x?

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