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3x^2-8x-11=13-6x
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Substract 13-6x from both sides.
ok
3x^2-8x-11=7x
I mean: 3x^2-8x-11-(13-6x)=13-6x-(13-6x)
ok then what would the next step be
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You have to put the equation in the canonical form: ax^2+bx+c=0 so you can use Bhaskara's Formula. Here we go, one step more to Bhaskaras: 3x^2-8x-11-(13-6x)=0
ok then do i factor or combine like terms
Combine: 3x^2-11-13+6x-8x=0 3x^2-2x-24=0
ok
how did you get 24?
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wouldn't it be 6x-8x?
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