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I still do not understand how to do this: Find the zeros of the function: y=(x-2)(x+9)... Help....... :/
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well the thing is someone already factor a quadratic for you. (x-2)(x+9)=0 results in x-2=0 and x+9=0 solve each individually. x=2 and x=-9
so the -2 and the 9 just switch signs?
yes. I just solve for them individuallay x-2=0 add 2 to both sides to isolate the x x+9=0 subtract 9 to both sides to isolate the x ------- here is the graph https://www.google.com/search?q=(x-2)(x%2B9)&rlz=1C1CHFX_enUS470US470&aq=f&sugexp=chrome,mod=11&sourceid=chrome&ie=UTF-8 Notice it intercepts the x axis the points i solved for
oh yes okay i see that
yay :D
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Haha Thank you (:
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