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Multiply: (2x + 4)(3x^2 - 2x - 10)
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\[\left( 2x+4 \right)\left( 3x ^{2} -2x-10\right) = 2x \left( 3x ^{2} -2x-10 \right)+4\left( 3x ^{2} -2x-10 \right)\] now, use distributive property and simplify
So the answer should be: 6x^2 - 4x - 20x + 12x^2 - 8x - 40 which breaks down into: 18x^2 - 32x - 40?
Should have some x^3 in there . . .
e.g. 2x*3x^2 = 6x^3.
Oh duh. Okay so. 6x^3 - 4x^2 - 20x + 12x^2 -8x - 40 so breaking down would be 6x^3 + 8x^2 - 28x - 40?
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That's it!
Yes.., it's correct... :)
Thanks for the help, this test seems impossible. <.>
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