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how do u solve 25y^2 - 49w^2
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are you familiar with the difference of squares? \[\huge a^2 - b^2 = (a+b)(a-b)\]
a little yes
good. so what is \(\sqrt{25y^2}\)
5y... idk
yes it's 5y
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now what is \(\sqrt{49w^2}\)
7w
right. so... a = 5y b = 7w substitute that into (a+b)(a-b) what do you get?
do you do foil?
no.. just put 5y into a and 7w into b in (a+b)(a-b)
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and thats your whole answer?
yes
oh... i feel stupid! :) thanks!
welcome
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