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square root of 28- the square root of 112 +3 square root 63
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hint: \[\sqrt 28 \implies \sqrt{4 \times 7} \implies 2 \sqrt 7\] \[\sqrt{112} \implies \sqrt{16 \times 7} \implies 4\sqrt 7\] \[\sqrt{63} \implies \sqrt{9 \times 7} \implies 3\sqrt 7\] does that help?
yea... somehow i got 7 root 7
nope. what is the value of \[2\sqrt 7 - 4\sqrt 7 + 3\sqrt 7\]
is it just root 7
yes
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ok...but does that include the 3 before the root 63?
what do you mean?
oh wait.. i did not see that o.O
sorry \(7\sqrt 7\) is right then
the problem is root 28 - root 112 + 3 root 63
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are you serious?
well thanks for the explanation, it helped!!!!
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